Answer (1 of 5) *A * \sin x=\dfrac 35\implies the angle x is inside a (3,4,5) right triangle Hence \cos x=\pm\dfrac 45 * \cos y=\dfrac 5{13}\implies the angle y is inside a (5,12,13) right triangle Hence \sin y=\pm\dfrac{12}{13} * Hence \tan x=\pm \dfrac 34, \tan y=\pm \dfrac{12}5 Now usSolution For The vertices of a variable triangle are (3,4), (5 cos theta,5 sin theta), and (5sintheta,5costheta) , whose theta=inRThe locus of its orthocenter is In triangle JKL, sin(b°) = 3/5 and cos(b°) =4/5 If triangle JKL is dilated by a scale factor of 2, what is ta Get the answers you need, now!
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Sin cos tan of 3 4 5 triangle
Sin cos tan of 3 4 5 triangle-If 35 is the upper limit of a class interval of class s;Answer (1 of 4) We have to use the sine rule here If the triangle is ABC we have angles A, B and C and sides AB, BC and CA The rule says that AB/sin = BC/sin(A) = CA/sin(B) In a 345 triangle = ABBCCA we know CA = 5 is the hypotenuse and its opposite angle B
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This value of sin(x) occurs in a 3,4,5 right angled triangle Here's a picture I made earlier In this triangle we have sin(A) = opposite hypotenuse = 3 5 cos(A) = adjacent hypotenuse = 4 5 tan(A) = opposite adjacent = 3 4 Hence if x is in Q1 and sin(x) = 3 5 then tan(x) = 3 4 What about other quadrants?Vertices of a variable triangle are 3 4 5 cos θ 5 sin θ and 5 sin θ 5 cos θ where θ ∈ RThen locus of its orthocenter is xy−12 x−y−72 = 100 xy−72 x−y−1The vertices of a variable triangle are (3, 4), (5 cos θ, 5 sin θ), a n d (5 sin θ, − 5 cos θ), w h e r e θ ϵ R then the locus of its orthocenter is A (x − 3) 2 (y − 4) 2 = 5 0 B (x y − 7) 2 (x − y − 7) 2 = 1 0 0 C (x y − 7) 2 (x − y 7) 2 = 1 0 0 D (x − y − 7) 2 (x − y − 7) 2 = 1 0 0 Medium Open in App Solution Verified by Toppr Correct
Mode is Middle most value Least frequent value Most fr; Any triangle whose sides are in the ratio 345 is a right triangle Such triangles that have their sides in the ratio of whole numbers are called #color(red)("Pythagorean Triples"# There are an infinite number of them, and this is just the smallest #csc theta = 1/ sin theta = 5/3# #cos theta = (AB) / (AC) = 4/5# #sec theta = 1 / cos theta = 5/4#Vertices of a variable triangle are (3, 4), (5 cos θ, 5 sin θ) and (5 sin θ, − 5 cos θ), where θ ∈ R Locus of its orthocentre is A (x y − 1) 2 (x − y − 7) 2 = 1 0 0 B (x y − 7) 2 (x − y − 1) 2 = 1 0 0 C (x y − 7) 2 (x y − 1) 2 = 1 0 0 D (x y − 7) 2 (x − y 1) 2 = 1 0 0 Hard Open in App Solution Verified by Toppr Correct option is D (x
Vertices of a variable triangle are (3, 4), (5 cos θ, 5 sin θ) and (5 sin θ, − 5 cos θ), where θ ∈ R Locus of it's orthocentre is A x 2 y 2 6 x 8 y − 2 5 = 0In a right triangle ABC, if sin A = 3/5, what is cos A?Vertices of a variable triangle are `(3, 4), (5 cos theta, 5 sin theta)` and `(5 sin theta, 5 cos theta)`, where `theta in R` Locus of its orthocentre is
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If the angle ofVertices of a variable triangle are (3, 4), (5 cos θ, 5 sin θ) and (5 sin θ, − 5 cos θ), where θ ∈ R Locus of it's orthocentre is View solution Locus of the mid points of the intercepts between the coordinate axes by the lines passing through (a, 0) does not intersect View solution View more Learn with content Watch learning videos, swipe through stories, and browse throughA 4/5 B 3/4 C 3/5 D 4/3 Please scroll down to see the correct answer and solution guide Right Answer is A SOLUTION Related Questions The ratio of the length of a rod and its shadow is 1√3;
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